5644. 得到子序列的最少操作次数
状态:未AC
代码:
class Solution {public:unordered_map<int, int> m;int minOperations(vector<int>& target, vector<int>& arr) {int n = target.size(), sz = 0;for (int i = 0; i < n; i++) m[target[i]] = i;int dp[100010];for (int i = 0; i < arr.size(); i++) {if (!m.count(arr[i])) continue;if (!sz || m[arr[i]] > dp[sz - 1]) {dp[sz] = m[arr[i]];sz++;} else {int id = lower_bound(dp, dp + sz, m[arr[i]]) - dp;dp[id] = m[arr[i]];}}return n - sz;}};
