https://leetcode.cn/problems/invert-binary-tree/
需要注意的点
- 递归到子节点, 从子节点开始翻转
翻转节点左右节点,递归处理左节点,然后递归右节点
# Definition for a binary tree node.# class TreeNode:# def __init__(self, val=0, left=None, right=None):# self.val = val# self.left = left# self.right = rightclass Solution:def invertTree(self, root: TreeNode) -> TreeNode:if not root:return rootleft = self.invertTree(root.left)right = self.invertTree(root.right)root.left = rightroot.right = leftreturn root
```python
Definition for a binary tree node.
class TreeNode:
def init(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution: def invertTree(self, root: TreeNode) -> TreeNode:
def traverse(node: TreeNode) -> TreeNode:if not node:returntmp = node.rightnode.right = node.leftnode.left = tmptraverse(node.left)traverse(node.right)traverse(root)return root
```
