实验一、认识EasycodeBoyPlus
实验二、 辗转相除法
求两个数的最大公约数的算法
主要思想:用两个数中的小的去除大的,将大的扔掉,然后再用两个数(余数与较小的数)中的小的去除大的、、、、,直到余数为零。
例:求(1397,2413)
2413=13971+1016;
1397=10161+381;
1016=3812+254;
381=2541+127;
254=1272+0
import java.util.Scanner**;public class GreatestCommonFactor {
第一种方法
public static int gcd(int a,int b){
//        int max1 = Math.max(a, b);
//        int min1 = Math.min(a, b);
//
//        while(min1>=0){
//
//            int temp=max1%min1;
//            System.out.println(max1+”=”+min1+”“+(max1/min1)+”+”+temp);
//            max1=min1;
//            min1=temp;
//            if(temp==0){
//                break;
//            }
//            //System.out.println(max1+”=”+min1+”“+(max1/min1)+”+”+temp);
//        }
//        return max1;
//    }
第二种方法
//    public static int gcd(int a,int b){
//        int max1 = Math.max(a, b);
//        int min1 = Math.min(a, b);
//
//        while(min1>=0){
//
//            int temp=max1%min1;
//            System.out.println(max1+”=”+min1+”“+(max1/min1)+”+”+temp);
//            max1=min1;
//            min1=temp;
//            if(temp==0){
//                break;
//            }
//            //System.out.println(max1+”=”+min1+”“+(max1/min1)+”+”+temp);
//        }
//        return max1;
//    }
第三种方法
//public static void main(String[] args) {//  
  // TODO 自动生成的方法存根
//    Scanner sc = new Scanner(System.in);
//    System.out.println(“输入第一个数,然后回车”);
//    int a = sc.nextInt();//    System.out.println(“输入第二个数,然后回车”);
//    int b = sc.nextInt();//    getResult(a,b);
//}
//    public static void getResult (int a,int b){
//       
 //获取大的值
//        int max = Math.max(a, b);
//        
//获取小的值
//        int min = Math.min(a, b);
//        int result = max % min;
//        System.out.println(max+”=”+min+”“+(max/min)+”+”+result);
//        if(result == 0){
//            return;
//        }else{
//            getResult(min,result)
//        }
//
//    }
实验三、加密算法实验之—————-异或运算实现
1. 随机产生2组二进制数,每组为32位。
1. 将这两组数进行异或运算。(按照运算规则)
要求:写成函数或者模块的形式,方便后续调用。
•异或运算
•运算符: 运算通常用符号“⊕”表示。
•运算规则:设逻辑变量A、B、C,它的运算规则为:A ⊕B = C ,读作:“A同B‘异或’等于C”。0⊕0 = 0 0⊕1 = 1
1⊕0 = 1 1⊕1 = 0
•结论:在A、B两个逻辑变量中,只要两个逻辑变量的值相同,“异或”运算的结果就为0;当两个逻辑变量的值不同时,“异或”运算的结果才为1。
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package test;
import java.util.Random;
import java.util.Scanner;
public class Test {
 
    public static void main(String[] args) {
  Scanner sc=new Scanner(System.in);
  int s=sc.nextInt();
 
     Random r=new Random();
     int a[]=new  int[s];  
  int b[]=new int[s];
 
 
  for(int i=0;i      int c=(int)r.nextInt((1)+1);
    a[i]=c;  
    System.out.print(c);
   
   
  }
  System.out.print(“\n”);
  for(int i=0;i      int d=(int)r.nextInt((1)+1);
   
    b[i]=d;
    System.out.print(d);
  }  
  System.out.print(“\n”);
  for(int i=0;i      int c [] = new int [s];
      c[i] = xor(a[i],b[i]);
      System.out.print(c[i]);
  }
 
    }
    static int xor(int a,int b){
 
  if( a == b){
      return 0;
  }
  return 1;
    }
}
实验四、
import com.sun.management.VMOption;
import java.beans.Customizer;
import java.util.Arrays;
import java.util.Scanner;
public class DES {
//初始置换
private int[] IP = {58,50,42,34,26,18,10,2,60,52,44,36,28,20,12,4,62,54,46,38,30,22,14,6,64,56,48,40,32,24,16,8,57,49,41,33,25,17,9,1,59,51,43,35,27,19,11,3,61,53,45,37,29,21,13,5,63,55,47,39,31,23,15,7};
//逆初始置换
private int[] IP_1={40,8,48,16,56,24,64,32,39,7,47,15,55,23,63,31,38,6,46,14,54,22,62,30,37,5,45,13,53,21,61,29,36,4,44,12,52,20,60,28,35,3,43,11,51,19,59,27,34,2,42,10,50,18,58,26,33,1,41,9,49,17,57,25};
//E扩展
private int[] E={32,1,2,3,4,5,4,5,6,7,8,9,8,9,10,11,12,13,12,13,14,15,16,17,16,17,18,19,20,21,20,21,22,23,24,25,24,25,26,27,28,29,28,29,30,31,32,1};
//P置换
private int[] P={16,7,20,21,29,12,28,17,1,15,23,26,5,18,31,10,2,8,24,14,32,27,3,9,19,13,30,6,22,11,4,25};
//
private static final int[][][] S_Box={
{
{14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7 },
{0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8 },
{4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0},
{4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0}},
{{ 15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10 },{ 3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5 },{ 0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15 },{ 13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9 } },{{ 10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8 },{ 13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1 },{ 13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7 },{ 1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12 } },{{ 7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15 },{ 13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9 },{ 10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4 },{ 3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14 } },{{ 2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9 },{ 14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6 },{ 4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14 },{ 11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3 } },{{ 12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11 },{ 10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8 },{ 9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6 },{ 4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13 } },{{ 4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1 },{ 13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6 },{ 1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2 },{ 6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12 } },{{ 13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7 },{ 1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2 },{ 7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8 },{ 2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11 } }};//PC-1private int[] PC1={57,49,41,33,25,17,9,1,58,50,42,34,26,18,10,2,59,51,43,35,27,19,11,3,60,52,44,36,63,55,47,39,31,23,15,7,62,54,46,38,30,22,14,6,61,53,45,37,29,21,13,5,28,20,12,4};//PC-2private int[] PC2={14,17,11,24,1,5,3,28,15,6,21,10,23,19,12,4,26,8,16,7,27,20,13,2,41,52,31,37,47,55,30,40,51,45,33,48,44,49,39,56,34,53,46,42,50,36,29,32};//Schedule of left shiftsprivate int[] LFT={1,1,2,2,2,2,2,2,1,2,2,2,2,2,2,1};//加密轮数private static final int LOOP_NUM=16;private String [] keys=new String [LOOP_NUM];private String []pContent;private String []cContent;private int origin_length;//16个子密钥private int[][] sub_key=new int[16][48];private String content;private int p_origin_length;public DES(String key,String content){this.content=content;p_origin_length=content.getBytes().length;generateKeys(key);}
//拆分分组
public byte[] deal(byte[] p,int flag){
origin_length=p.length;
int g_num;
int r_num;
g_num=origin_length/8;
r_num=8-(origin_length-g_num*8);//8不填充
byte[] p_padding;
/填充/
if (r_num<8){
p_padding=new byte[origin_length+r_num];
System.arraycopy(p,0,p_padding,0,origin_length);
for(int i=0;i
}
}else{p_padding=p;}g_num=p_padding.length/8;byte[] f_p=new byte[8];byte[] result_data=new byte[p_padding.length];for(int i=0;i<g_num;i++){System.arraycopy(p_padding,i*8,f_p,0,8);System.arraycopy(descryUnit(f_p,sub_key,flag),0,result_data,i*8,8);}if (flag==0){//解密byte[] p_result_data=new byte[p_origin_length];System.arraycopy(result_data,0,p_result_data,0,p_origin_length);return p_result_data;}return result_data;
}
/加密/
public byte[] descryUnit(byte[] p,int k[][],int flag){
int[] pbit=new int[64];
StringBuilder stringBuilder=new StringBuilder();
for(int i=0;i<8;i++){
String p_b=Integer.toBinaryString(p[i]&0xff);
while (p_b.length()%8!=0){
p_b=”0”+p_b;
}
stringBuilder.append(p_b);
}
String p_str=stringBuilder.toString();
for(int i=0;i<64;i++){
int p_t=Integer.valueOf(p_str.charAt(i));
if(p_t48){
p_t=0;
}else if(p_t49){
p_t=1;
}else{
System.out.println(“To bit error!”);
}
p_bit[i]=p_t;
}
/**_IP置换**/
int [] p_IP=new int[64];
for (int i=0;i<64;i++){
p_IP[i]=p_bit[IP[i]-1];
}
if (flag == 1) { // 加密
for (int i = 0; i < 16; i++) {
L(p_IP, i, flag, k[i]);
}
} else if (flag == 0) { // 解密
for (int i = 15; i > -1; i—) {
L(p_IP, i, flag, k[i]);
}
}
int[] c=new int[64];
for(int i=0;i
}
byte[] c_byte=new byte[8];
for(int i=0;i<8;i++){
c_byte[i]=(byte) ((c[8_i]<<7)+(c[8_i+1]<<6)+(c[8_i+2]<<5)+(c[8_i+3]<<4)+(c[8_i+4]<<3)+(c[8_i+5]<<2)+(c[8_i+6]<<1)+(c[8_i+7]));
}
return c_byte;
}public void L(int[] M, int times, int flag, int[] keyarray){int[] L0=new int[32];int[] R0=new int[32];int[] L1=new int[32];int[] R1=new int[32];int[] f=new int[32];System.arraycopy(M,0,L0,0,32);System.arraycopy(M,32,R0,0,32);L1=R0;f=fFuction(R0,keyarray);for(int j=0;j<32;j++){R1[j]=L0[j]^f[j];if (((flag == 0) && (times == 0)) || ((flag == 1) && (times == 15))) {M[j] = R1[j];M[j + 32] = L1[j];}else {M[j] = L1[j];M[j + 32] = R1[j];}}}public int[] fFuction(int [] r_content,int [] key){int[] result=new int[32];int[] e_k=new int[48];for(int i=0;i<E.length;i++){e_k[i]=r_content[E[i]-1]^key[i];}/********S盒替换:由48位变32位,现分割e_k,然后再进行替换*********/int[][] s=new int[8][6];int[]s_after=new int[32];for(int i=0;i<8;i++){System.arraycopy(e_k,i*6,s[i],0,6);int r=(s[i][0]<<1)+ s[i][5];//横坐标int c=(s[i][1]<<3)+(s[i][2]<<2)+(s[i][3]<<1)+s[i][4];//纵坐标String str=Integer.toBinaryString(S_Box[i][r][c]);while (str.length()<4){str="0"+str;}for(int j=0;j<4;j++){int p=Integer.valueOf(str.charAt(j));if(p==48){p=0;}else if(p==49){p=1;}else{System.out.println("To bit error!");}s_after[4*i+j]=p;}}/******S盒替换结束*******//****P盒替代****/for(int i=0;i<P.length;i++){result[i]=s_after[P[i]-1];}return result;}/**生成子密钥**/public void generateKeys(String key){while (key.length()<8){key=key+key;}key=key.substring(0,8);byte[] keys=key.getBytes();int[] k_bit=new int[64];//取位值for(int i=0;i<8;i++){String k_str=Integer.toBinaryString(keys[i]&0xff);if(k_str.length()<8){for(int t=0;t<8-k_str.length();t++){k_str="0"+k_str;}}for(int j=0;j<8;j++){int p=Integer.valueOf(k_str.charAt(j));if(p==48){p=0;}else if(p==49){p=1;}else{System.out.println("To bit error!");}k_bit[i*8+j]=p;}}//k_bit是初始的64位长密钥,下一步开始进行替换/***********PC-1压缩****************/int [] k_new_bit=new int[56];for(int i=0;i<PC1.length;i++){k_new_bit[i]=k_bit[PC1[i]-1];}/**************************/int[] c0=new int[28];int[] d0=new int[28];System.arraycopy(k_new_bit,0,c0,0,28);System.arraycopy(k_new_bit,28,d0,0,28);for(int i=0;i<16;i++){int[] c1=new int[28];int[] d1=new int[28];if(LFT[i]==1){System.arraycopy(c0,1,c1,0,27);c1[27]=c0[0];System.arraycopy(d0,1,d1,0,27);d1[27]=d0[0];}else if(LFT[i]==2){System.arraycopy(c0,2,c1,0,26);c1[26]=c0[0];c1[27]=c0[1];//这里手残之前写成c1System.arraycopy(d0,2,d1,0,26);d1[26]=d0[0];d1[27]=d0[1];}else{System.out.println("LFT Error!");}int[] tmp=new int[56];System.arraycopy(c1,0,tmp,0,28);System.arraycopy(d1,0,tmp,28,28);for (int j=0;j<PC2.length;j++){//PC2压缩置换sub_key[i][j]= tmp[PC2[j]-1];}c0=c1;d0=d1;}}public static void main(String []args){Scanner sc=new Scanner(System.in);String origin=sc.nextLine();System.out.println("原文:"+origin);DES customerDES=new DES("密码学专栏", origin);byte[] c=customerDES.deal(origin.getBytes(),1);System.out.println("密文:\n"+new String(c));byte[] p=customerDES.deal(c,0);byte[] p_d=new byte[origin.getBytes().length];System.arraycopy(p,0,p_d,0,origin.getBytes().length);System.out.println("明文:\n"+new String(p));}
}
