10.28

for的使用

#include<stdio.h>
int main(void)
{
    int count;
    for(count = 1;count<=10;count += 2){
        printf("%d\n",count);
    }
    return 0;
 }

#include<stdio.h>
int main(void)
{
    int count,num;
    for(count = 1;count<=10;count++){
        num = 2*count -1;
        printf("%d\n",num);
    }
    return 0;
 }

#include<stdio.h>
int main(void)
{
    int count,num;
    for(count = 1;count<=10;count++){
        if(count % 2 == 1){
        printf("%d\n",count);}
    }
    return 0;
 }

#include<stdio.h>
int main(void)
{
    int a;
    for(a =1;a <=10;a++){
       if(a % 3!=0 && a % 2 == 0){
           printf("%d\n",a);
       }    
    }
    return 0;
}

#include<stdio.h>
int main(void)
{
    int a;
    for(a =2;a <=10;a+=2){
       if(a % 3!=0 ){
           printf("%d\n",a);
       }    
    }
    return 0;
}

#include<stdio.h>
int main(void)
{
    int a,n,sum = 0;
    printf("请输入一个值：\n");
    scanf("%d",&n);
    for(a = 1;a<=n;a++){
        sum = a + sum;
    } 
    printf("sum = %d",sum);
    return 0;
 }

#include<stdio.h>
 int main(void)
 {
     int a,n;
     char l = '*';
     printf("请输入一个数字：");
    scanf("%d",&a);
    for(n = 1;n<=a;n++){
        printf("%c",l);
    }  
    return 0;
 }

#include<stdio.h>
 int main(void)
 {
     int a,n;
     printf("输入一个数字;");
     scanf("%d",&a);
     for(n = 1;n<=a;n++){
         if(a % n==0){
         printf("%d\n",n);
     }
     }
     return 0;
 }

break和continue述句

break 中断目前所属的重复执行语句

 for(   ;   ;   ){
     if(  ){   
        break;     //可直接跳出for的循环
     }
 }

continue 在重复执行述句中跳过后面的语句，继续循环

for(   ;   ;   ){
     if(  ){   
       continue;     //直接跳到for循环，而不输出
     }
    printf("   ") 
 }