输入一个链表的头节点,从尾到头反过来返回每个节点的值(用数组返回)。
示例 1:
输入:head = [1,3,2]
输出:[2,3,1]
限制:0 <= 链表长度 <= 10000
方法一:(递归)
/*** Definition for singly-linked list.* function ListNode(val) {* this.val = val;* this.next = null;* }*//*** @param {ListNode} head* @return {number[]}*/var reversePrint = function(head) {if(head==null) return [];return [...reversePrint(head.next),head.val]};
方法二:(unshift)
/*** Definition for singly-linked list.* function ListNode(val) {* this.val = val;* this.next = null;* }*//*** @param {ListNode} head* @return {number[]}*/var reversePrint = function(head) {let res = []while(head){res.unshift(head.val)head = head.next}return res};
