SQL | 距离sql

#SQL
SELECT 
    es_name, 
    es_lon, 
    es_lat, 
    ROUND( 
        6378.138 * 2 * ASIN( 
            SQRT( 
                POW( 
                    SIN( 
                        ( 
                            30.611842 * PI() / 180 - es_lat * PI() / 180 
                        ) / 2 
                    ), 
                    2 
                ) + COS(30.611842 * PI() / 180) * COS(es_lat * PI() / 180) * POW( 
                    SIN( 
                        ( 
                            104.074666 * PI() / 180 - es_lon * PI() / 180 
                        ) / 2 
                    ), 
                    2 
                ) 
            ) 
        ) * 1000 
    ) AS distance_um 
FROM 
    c_ershuai 
ORDER BY 
    distance_um ASC